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13 April, 14:34

the sum of two numbers is 21 if 8 less than the sum of the two numbers is 5 more than triple the smaller number find the two numbers

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  1. 13 April, 16:44
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    x + y = 21

    x + y - 8 = 3*y + 5

    Subtract y from both sides.

    x - 8 = 3y - y + 5

    x - 8 = 2y + 5 Substitute x = 21 - y into the equation

    21 - y - 8 = 2y + 5

    13 = 3y + 5 Subtract 5 from both sides

    13 - 5 = 3y

    8 = 3y Divide by 3

    y = 8/3

    x + y = 21

    x + 8/3 = 21

    x = 21 - 8/3

    x = 18 1/3 or 18.333333

    Check

    The smaller number is 8/3

    x + y - 8 = 3 * (8/3) + 5 Remember that x + y = 21

    21 - 8 = 8 + 5

    13 = 13 and they check. Which one is the smaller number does not become a factor until you check your answer.
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