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19 October, 06:10

What is the range of the function y=x^2-5 where 0
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  1. 19 October, 07:48
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    The range is the bounds on y. If 0
    Plugging these values of x into the function gives y = (10) ^2-5=100-5=95 and y=0-5=-5

    However, since x can't actually equal 0 and 10, y cannot be exactly equal to - 5 and 95. Therefore, the range is - 5
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