Suppose y = 2x + 1, where x and y are functions of t. (a) if dx/dt = 3, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find dx/dt when x = 40. dx dt =

Step-by-step explanation:

If y = 2x + 1, then dy/dt = 2 (dx/dt).

If y = 2x + 1, then y = 2 (40) + 1 when 40 is substituted for x. y = 81.

(a) if dx/dt = 3, find dy/dt when x = 4:

Replacing dx/dt with 3 in dy/dt = 2 (dx/dt) yields dy/dt = 2 (3) = 6.

(b) if dy/dt = 2, find dx/dt when x = 40:

Replacing dy/dt with 2 in dy/dt = 2 (dx/dt) results in 2 = 2 (dx/dt), so dx/dt must be 1.