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28 January, 10:03

What is Y = 2x^2 + 7x + 5

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  1. 28 January, 11:09
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    x = sqrt (y/2 + 9/16) - 7/4 or x = - sqrt (y/2 + 9/16) - 7/4

    Step-by-step explanation:

    Solve for x:

    y = 2 x^2 + 7 x + 5

    y = 2 x^2 + 7 x + 5 is equivalent to 2 x^2 + 7 x + 5 = y:

    2 x^2 + 7 x + 5 = y

    Divide both sides by 2:

    x^2 + (7 x) / 2 + 5/2 = y/2

    Subtract 5/2 from both sides:

    x^2 + (7 x) / 2 = y/2 - 5/2

    Add 49/16 to both sides:

    x^2 + (7 x) / 2 + 49/16 = y/2 + 9/16

    Write the left hand side as a square:

    (x + 7/4) ^2 = y/2 + 9/16

    Take the square root of both sides:

    x + 7/4 = sqrt (y/2 + 9/16) or x + 7/4 = - sqrt (y/2 + 9/16)

    Subtract 7/4 from both sides:

    x = sqrt (y/2 + 9/16) - 7/4 or x + 7/4 = - sqrt (y/2 + 9/16)

    Subtract 7/4 from both sides:

    Answer: x = sqrt (y/2 + 9/16) - 7/4 or x = - sqrt (y/2 + 9/16) - 7/4
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