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3 July, 05:13

What is the sum of ten terms of an infinite geometric series if the first term is 8 and the ratio is 1/2

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  1. 3 July, 08:49
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    We use the formula:

    S 10 = 8 · [ (1/2) ^9 - 1] / (1/2 - 1);

    Then, S 10 = 8 · (1/512 - 1) / (1/2 - 1);

    S 10 = 8 · ( - 511 / 512) / (-1 / 2);

    S 10 = ( - 511 / 64) · ( - 2);

    S 10 = + 511 / 32;

    S 10 = 15.96;
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