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20 January, 22:43

BD is a diameter of circle O. If m∠ACB = 30°, what is m∠DBA?

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Answers (2)
  1. 21 January, 01:03
    0
    m∠DBA = 60º

    Step-by-step explanation:

    Angle subtended by the diameter is 90º:

    ⇒ m∠DAB = 90º

    Angles in a circle formed by the same arc are equal:

    ⇒ ∠ ADB = ∠ACB

    ⇒ m∠ ADB = 30º

    Sum of angles in a triangle is 180º:

    ⇒ m∠DBA + m∠DAB + m∠BDA = 180º

    ⇒ m∠DBA = 180° - 90° - 30°

    ⇒ m∠DBA = 60°
  2. 21 January, 01:24
    0
    it is 60
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