When the polynomial 4x^4 - 13x^2 - 2x is divided by the polynomial x - 2, x-2, what is the remainder?

Question

Mathematics

Annabel Soto

12 December, 03:22

When the polynomial 4x^4 - 13x^2 - 2x is divided by the polynomial x - 2, x-2, what is the remainder?

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Answers (1)

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Olivia Mcdowell · Answer 1

Let p (x) = 4x^4-13x^2-2x

The zero of x-2 is 2

putting x = 2 in p (x), we get,

p (2) = 4*2^4-13*2^2-2*2

= 64 - 52 - 4

= 64 - 56

= 8

Therefore, remainder = 8