A sequence is defined by the function f (n) = f (n-1) + 5. Where n represents the number of the term for n>1 and f (1) = -4. What are the first four terms of the sequence

The first four terms of the above sequence are 1, 6, 11, 16.

Step-by-step explanation:

A sequence is defined by the function f (n) = f (n-1) + 5.

Where n represents the number of the term for n>1

First Put n = 2

f (2) = f (2-1) + 5.

= f (1) + 5

= - 4 + 5

= 1

Second Put n = 3

f (3) = f (3-1) + 5.

= f (2) + 5

= 1 + 5

= 6

Third Put n = 4

f (4) = f (4-1) + 5.

= f (3) + 5

= 6 + 5

= 11

Second Put n = 5

f (5) = f (5-1) + 5.

= f (4) + 5

= 11 + 5

= 16

Therefore the first four terms of the above sequence are 1, 6, 11, 16.

Answer: The first four terms are - 4, 1, 6 and 11.

Step-by-step explanation: The function which defines the given sequence is

f (n) = f (n-1) + 5, where 'n' is the number of terms for n>1 and the first term is

f (1) = - 4.

So, second term = f (2) = f (1) + 5 = - 4+5 = 1.

Third term = f (3) = f (2) + 5 = 1+5 = 6.

Fourth term = f (4) = f (3) + 5 = 6+5 = 11.

Thus, the first four terms of the sequence are - 4, 1, 6 and 11.