A jar contains 4 red marbles, 4 green marbles, and 5 blue marbles.

If we choose a marble, then another marble without putting the first one back in the jar, what is the probability that the first marble will be blue and the second will be green?

20/156 or 5/39

Step-by-step explanation:

the first part of the equation will be:

5/13 (5 is how many blue and 13 is altogether)

the next part of this equation is the green marble. Because we didn't put the blue marble back, the next part of the equation will be:

4/12 (4 is how many green and 12 is altogether now that one blue was taken out)

and from there, you multiply 5/13 with 4/12, with will give you 20/156, or 5/39 if you simplify.