Ask Question
8 April, 15:05

3 rooms are occupied by disease x, 4 by disease y, 2 rooms by disease z and 1 by disease a. What is the probability that a random room does not contain disease y?

+3
Answers (1)
  1. 8 April, 18:54
    0
    6/10

    Step-by-step explanation:

    [P (x) + P (z) + P (a) ]/P (all) = (3+2+1) / (3+4+2+1) = 6/10
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “3 rooms are occupied by disease x, 4 by disease y, 2 rooms by disease z and 1 by disease a. What is the probability that a random room does ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers