Givin sin0 = 12/13, find sec (0)

A. Sec (0) = 13/12

B. Sec (0) = 5/13

C. Sec (0) = 5/12

D. Sec (0) = 13/5

Question

Mathematics

Clay

14 January, 11:45

Givin sin0 = 12/13, find sec (0)

A. Sec (0) = 13/12

B. Sec (0) = 5/13

C. Sec (0) = 5/12

D. Sec (0) = 13/5

+4

Answers (1)

Know the Answer?

Lindsay Oneal · Answer 1

D. sec (a) = 13/5

Step-by-step explanation:

if sin (a) = 12/13, then cos (a) = 5/13, because of 5-12-13 triangles

sec (a) = 1/cos (a)

1 / (5/13) = 13/5

sec (a) = 13/5

Givin sin0 = 12/13, find sec (0)A. Sec (0) = 13/12B. Sec (0) = 5/13C. Sec (0) = 5/12D. Sec (0) = 13/5

Givin sin0 = 12/13, find sec (0)

A. Sec (0) = 13/12

B. Sec (0) = 5/13

C. Sec (0) = 5/12

D. Sec (0) = 13/5