A hemispherical bowl has a radius of 3.5 cm. What would be the

volume of water it would contain?

89.78 cm^3

Step-by-step explanation:

The volume of a hemisphere is half of the volume of a sphere.

The volume of a sphere:

4/3 π r^3

Multiply by 1/2

1/2 (4/3 π r^3)

2/3 π r^3

Volume of a hemisphere: 2/3 π r^3

The radius is 3.5 centimetres. Substitute 3.5 in for r.

v=2/3 π r^3

v=2/3 π 3.5^3

Evaluate the exponent

v=2/3 * π * 42.875

Multiply all the numbers together

v=89.7971900151

The volume of water it would contain is about 89.78 cm^3

89.80 cm cubed

Step-by-step explanation:

A hemisphere is essentially just half of a sphere. We want to find its volume.

The volume of a sphere is denoted by: V = (4/3) π * r³, where r is the radius. That means the volume of a hemisphere, which is half a sphere, will be denoted by: V = (1/2) * (4/3) π * r³ = (2/3) π * r³.

Here, the radius is 3.5, so plug this in:

V = (2/3) π * r³

V = (2/3) π * (3.5) ³ ≈ 89.80 cm cubed