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21 January, 01:55

Identify the equation of the circle that has its center at (7, - 24) and passes through the origin.

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  1. 21 January, 03:41
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    The equation of this line would be (x - 7) ^2 + (y + 24) ^2 = 625

    This is because of the base equation for circles, which is:

    (x - x1) ^2 + (y - y1) ^2 = r^2

    In which, x1 is the x-coordinate to the center, y1 is the y-coordinate to the center and r is the radius.

    So we start by putting in out known values.

    (x - 7) ^2 + (y + 24) ^2 = r^2

    However, we still don't know the r value. To find it, we must use the Pythagorean Theorem to find the distance between the center and the origin.

    a^2 + b^2 = c^2

    7^2 + 24^2 = c^2

    49 + 576 = c^2

    625 = c^2

    25 = c

    So we know the radius must be 25. So we can plug that into what we already had.

    (x - 7) ^2 + (y + 24) ^2 = 25^2

    (x - 7) ^2 + (y + 24) ^2 = 625
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