Y = 5x-40

y-3x=-24

(Solve the system algebraically by any method and show work)

Substitution ...

y = 5x - 40 ... so we sub in 5x - 40 in for y in the other equation

y - 3x = - 24

5x - 40 - 3x = - 24

5x - 3x = - 24 + 40

2x = 16

x = 16/2

x = 8

y = 5x - 40

y = 5 (8) - 40

y = 40 - 40

y = 0

solution is (8,0)