Is it is it possible to have 43 pencils and divide the pencils into groups with the same number of pencils with none left over

we have given 43 pencils

we need to divide it equally so that none can be without groups.

we need to find the factors of 43.

we know that 43 is a prime number. which cannot be divided. so it is not possible to divide the 43 pencils with none left over.

TO find out the answer, we need to check whether 43 have any factors or not

43 is a prime number that is it have only two factors 1 and 43. So either 1 will take whole 43 pencils or 43 will take one pencil each.

So it is not possible to divide 43 pencils into groups with the same number of pencils and none left over.