What is x^2-12x+23=7 in vertex form?

y = (x - 6) ^2 - 20

Step-by-step explanation:

Let's start by completing the square for x^2 - 12x. Half of the coefficient of x is (1/2) (-12), or - 6. Square this and add it to x^2 - 12x, and then subtract it:

x^2 - 12x + 36 - 36 + 23 = 7

Rewriting the first three terms,

(x - 6) ^2 - 13 = 7, or

y = (x - 6) ^2 - 20

The vertex is located at (h, k), which here is (6, - 20).