In the game of roulette, a player can place a $66 bet on the number 66 and have a startfraction 1 over 38 endfraction 1 38 probability of winning. if the metal ball lands on 66 , the player gets to keep the $66 paid to play the game and the player is awarded an additional $210210. otherwise, the player is awarded nothing and the casino takes the player's $66. what is the expected value of the game to the player? if you played the game 1000 times, how much would you expect to lose?

Question

Harrell

17 September, 09:43

+3

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Jordon David · Answer 1

If you played 1000 times there is a possibility of winning 380 times which could give you $79,879,800 if you played on number 66 each time.