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27 March, 22:45

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a speed of 10.0

meters/second. What is the emf produced?

OA.

10.65 volts

OB.

9.35 volts

C.

0.90 volts

OD

4.4 volts

+1
Answers (1)
  1. 28 March, 02:45
    0
    Given:

    length of the wire = 0.20 meters

    magnetic field strength = 0.45 newtons/amperes meter

    speed = 10.0 meters per second

    emf = B * l * v

    B = flux density; l = length of the wire; v = velocity of the conductor

    emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

    emf = 0.90 volts

    The emf produced is 0.90 volts.
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