Mathematics

Guest

4 October, 00:15

How many real solutions does the equation 0.2x^5-2x^3+1.8x+k=0 have when k=1?

+3

Answers (1)

Know the Answer?

Not Sure About the Answer?

Get an answer to your question ✅ “How many real solutions does the equation 0.2x^5-2x^3+1.8x+k=0 have when k=1? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.

Search for Other Answers

You Might be Interested in

Solve the equation by factoring. c2 - 8c = 0

Find the least common multiple to determine the least common denominator for 2/3, 5/6 and 9/4

The population of Forestville is 83,277. What is the population to the nearest thousand?

Solve using Distributive property - 3 (-4v^3-2+2y^2)

negative one over eight (x + 35) = - 7

New Questions in Mathematics

Which polynomial is a trinomial? 6 - 2x^3 - 4x^2 + x^5 1 - 2x + 5x^4 1-x 2p^3 - p

Euler's formula, V - E + F = 2, relates the number of vertices V, the number of edges E, and the number of faces F, of a polyhedron. Solve Euler's formula for E.

Are all prime numbers greater than 2 odd number. are all composite numbers even numbers.

What is 15 divided by 10.05 in the standard algorithm 1 way

The average time it takes a swimmer to complete a lap is represented by the variable t. which set of numbers best describes the value of the variable?