2/3[8 (5-2) ^{2}+3*2]

How do I distribute the 2/3 and then solve the rest?

Before I distribute, I solve the inside first:

2/3[8 (3) ^2+6]

2/3[8 (9) + 6]

2/3[72+6]

2/3[78]

2*26 = 52 is the answer

another way:

2/3[8 (3) ^2+6]

2/3[8 (9) + 6]

2/3[72+6]

(2/3) * 72 + (2/3) * 6

2*24+2*2

48+4 = 52