Ask Question
9 August, 02:13

y=2x^2/3x^2-16 what is the horizontal asymptote for the above function? round to the nearest thousandth.

+4
Answers (1)
  1. 9 August, 04:04
    0
    0.667

    Step-by-step explanation:

    Performing the indicated division gets you ...

    y = (2/3) + (32/3) / (3x^2 - 16)

    The term containing x goes to zero as x gets large, leaving y = 2/3 as the horizontal asymptote. In decimal form, this is approximately ...

    y = 0.667
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “y=2x^2/3x^2-16 what is the horizontal asymptote for the above function? round to the nearest thousandth. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers