y=2x^2/3x^2-16 what is the horizontal asymptote for the above function? round to the nearest thousandth.

0.667

Step-by-step explanation:

Performing the indicated division gets you ...

y = (2/3) + (32/3) / (3x^2 - 16)

The term containing x goes to zero as x gets large, leaving y = 2/3 as the horizontal asymptote. In decimal form, this is approximately ...

y = 0.667