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24 November, 06:27

The arithmetic sequence a_ia i a, start subscript, i, end subscript is defined by the formula: a_1 = - 53a 1 = -53a, start subscript, 1, end subscript, equals, minus, 53 a_i = a_{i - 1} + 6a i = a i-1 + 6a, start subscript, i, end subscript, equals, a, start subscript, i, minus, 1, end subscript, plus, 6 Find the sum of the first 880880880 terms in the sequence.

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  1. 24 November, 08:14
    0
    S880 = 2,273,920

    Step-by-step explanation:

    For an arithmetic sequence, a1 = - 53 and

    when n = 2,

    The first 3 terms forms an arithmetic sequence as shown;

    -53, - 47, - 41 ...

    Sum of nth term of an arithmetic sequence is expressed as;

    a is the first term = - 53

    n is the number of term = 880 (since we want to find the sum of the first 880 terms)

    d is the common difference = 6

    S880 = 880/2 {2 (-53) + (880-1) 6}

    S880 = 440{-106 + (879) 6}

    s880 = 440{-106+5274}

    S880 = 440 * 5168

    S880 = 2,273,920
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