What are the zeros of the quadratic function f (w) = 2w^2+7w-4

Answer: w = 1/2 and w = - 4

Step-by-step explanation:

2w^2+7w-4=0

The quadratic formula is (-b + - √b^2-4ac) / 2a

In this case a=2, b=7, c = - 4

(-7 + - √7^2 - 4 (2) (-4)) / 2 (2)

(-7 + - √49+32) / 4

(-7 + - √81) / 4

(-7+9) / 4 and (-7-9) / 4

2/4 and - 16/4

1/2 and - 4

Answer:f (w) = w^3 + 7/2w^2-4w+c