Ask Question
31 August, 04:10

How many pounds of carbon dioxide would you prevent from entering the atmosphere in one year, if you were to replace a 100-watt light bulb with a CFL bulb that uses 32 watts in a fixture that you have on 3 hours per day?

+3
Answers (1)
  1. 31 August, 04:40
    0
    Answer: 73.596 pounds

    Step-by-step explanation:

    We know that a kWh is related to emissions of 0.9884 lbs.

    Then for the 100-watt light bulb we have.

    It is used 3 hours per day, so it consumes 3*100 = 300 Wh

    and 1 kWh = 1000 Wh, so 300wh = 0.3 kWh.

    Then, in one day, this light bulb produces:

    0.3*0.9884 lbs = 0.297 lbs of carbon dioxide.

    In one year, it produces:

    365*0.297 lb = 108.230 lb

    The 32 what light bulb is also used 3 hours per day:

    3h*32W = 96 Wh or 0.096 kWh.

    In a day, this light bulb produces:

    0.096*0.9884 = 0.095 lb of carbon dioxide.

    In a year, it produces:

    365*0.095 lb = 34.633 lb.

    The difference in the year production is:

    D = 108.230 lb - 34.633 lb = 73.596 lb.

    This means that using the 32 watts bulb prevents, in a year, 73.596 pounds of carbon dioxide to enter in the atmosphere.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many pounds of carbon dioxide would you prevent from entering the atmosphere in one year, if you were to replace a 100-watt light bulb ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers