The function f (x) = x2 - 5x - 6, written

correctly in factored form, and its zeros are

A. f (x) = (x - 2) (x + 3) with zeros of

-2 and 3

B. f (x) = (x+3) (x - 2) with zeros of

-3 and 2

C. f (x) = (x - 6) (x + 1) with zeros of

-6 and 1

D. f (x) = (x + 1) (x - 6) with zeros of

-1 and 6

D

Step-by-step explanation:

Given

f (x) = x² - 5x - 6

To find the zeros let f (x) = 0, that is

x² - 5x - 6 = 0

Consider the factors of the constant term ( - 6) which sum to give the coefficient 0f the x - term ( - 5)

The factors are - 6 and + 1, since

- 6 * 1 = - 6 and - 6 + 1 = - 5, thus

(x + 1) (x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 6 = 0 ⇒ x = 6