What is the 66th term of the arithmetic sequence - 28, - 45, - 62

Answer:-1133

Step-by-step explanation:

-28,-45,-62

First term=a=-28

Common difference=d=-45 - (-28)

d=-45+28

d=-17

Using the formula

Tn=a + d x (n-1)

T66 is the 66th term

T66=-28 + (-17) (66 - 1)

T66=-28 + (-17) (65)

T66=-28 - 1105

T66=-1133

66th term=-1133

a (66) = - 1133

Step-by-step explanation:

The common difference here is - 17. Note that - 45 is equal to the previous value (-28), and that subtracting 17 from - 28 yields - 45.

Then the explicit equation of this arithmetic sequence is

a (n) = - 28 - 17 (n - 1)

and the 66th term is a (66) = - 28 - 17 (65), or a (66) = - 1133