What is the solution to the system of equations

x = y + 4

2x - 3y = - 2

Answer: x = 14 and y = 10

Step-by-step explanation: What we have in the question is a pair of simultaneous equations as follows (

x = y + 4 - - - (1)

2x - 3y = - 2 - - (2)

Looking at both equations, one of the variables has a coefficient of 1, and as a result of that, we shall use the substitution method.

From equation (1), x = y + 4

Substitute for the value of x in equation (2)

2x - 3y = - 2

2 (y + 4) - 3y = - 2

2y + 8 - 3y = - 2

-y + 8 = - 2

Subtract 8 from both sides of the equation

-y + 8 - 8 = - 2 - 8

-y = - 10

Divide both sides of the equation by - 1

y = 10

Having calculated y, substitute for the value of y into equation (1)

x = y + 4

x = 10 + 4

x = 14

Therefore, x = 14 and y = 10