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17 June, 22:05

I have a Algebra 2 question

f (x) = 5x + 4 and g (x) = x^2 - 5

find g (f (4))

+4
Answers (2)
  1. 17 June, 22:12
    0
    g (f (4)) = 571

    Step-by-step explanation:

    g (f (4))

    We need to evaluate the function f at x=4

    f (4) = 5*4 + 4

    f (4) = 20+4

    f (4) = 24

    Now we have to evaluate the function g at 24

    g (24) = 24^2 - 5

    576 - 5

    571

    g (f (4)) = 571
  2. 17 June, 23:05
    0
    Answer: 571

    To get this answer, we first need to compute the value of f (4). This happens when we plug x = 4 into f (x)

    f (x) = 5x + 4

    f (4) = 5*4+4 ... each x replaced with 4

    f (4) = 20+4

    f (4) = 24

    Now replace every 'x' in g (x) with f (4) like so

    g (x) = x^2 - 5

    g (x) = (x) ^2 - 5

    g (f (4)) = (f (4)) ^2 - 5 ... every x replaced with f (4)

    g (f (4)) = (24) ^2 - 5 ... see note below

    g (f (4)) = 576 - 5

    g (f (4)) = 571

    note: the f (4) on the right hand side of that equation is replaced with 24, because we found earlier that f (4) = 24. In other words, f (4) is the same as 24.
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