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9 August, 23:27

If $f (x) = ax^6-bx^4+x-1$ and $f (2) = 5$, then what is the value of $f (-2) $?

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  1. 10 August, 03:12
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    f (-2) = 1

    Step-by-step explanation:

    The unknown terms are of even degree, so will have the same value for x=2 and x=-2. If we call those terms Q, then ...

    ... f (2) = Q + 2 - 1 = 5

    ... Q = 4

    ... f (-2) = Q - 2 - 1 = 4 - 3

    ... f (-2) = 1
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