The perimeter of rectangle ABCD is 42 cm and the area is 80 cm2. Which equation can be used to find the dimensions of the rectangle? (Hint: Set up a system of equations).

xy + 2x + 2y = (42) (80)

x^2 + 80x - 42 = 0

x^2 - 42x + 80 = 0

x^2 - 21x + 80 = 0

Question

America Sandoval

28 September, 06:30

+4

Answers (1)

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Savannah Gross · Answer 1

Don't hold me accountable but I believe it is the 2nd equation.

The perimeter of rectangle ABCD is 42 cm and the area is 80 cm2. Which equation can be used to find the dimensions of the rectangle? (Hint: Set up a system of equations).xy + 2x + 2y = (42) (80)x^2 + 80x - 42 = 0x^2 - 42x + 80 = 0x^2 - 21x + 80 = 0