What is the vertex of f (x) = (x-8) (x-2)

Hello!

To find the vertex of f (x), we can simplify this function into standard form.

f (x) = (x - 8) (x - 2)

f (x) = x² + - 10x + 16

With the equation in standard form, we use the formula: x = - b/2a. Then, we substitute the value of x into the equation to solve for the y-value.

x = - (-10) / 2 (1)

x = 10 / 2

x = 5

Then, we substitute x = 5 into the original equation.

f (x) = (5 - 8) (5 - 2)

f (x) = - 3 (3)

f (x) = - 9

Therefore, the vertex of f (x) is (5, - 9).