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21 October, 01:58

How do you expand (x-4) ^2?

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Answers (2)
  1. 21 October, 02:16
    0
    Answer: x^2 - 8x + 16

    Let y = x-4

    (x-4) ^2 = (x-4) * (x-4)

    (x-4) ^2 = y * (x-4) ... replace one copy of (x-4) with y

    (x-4) ^2 = x*y - 4*y ... distribute

    (x-4) ^2 = x * (y) - 4 (y)

    (x-4) ^2 = x (x - 4) - 4 (x - 4) ... replace y with x-4

    (x-4) ^2 = x^2-4x-4x+16 ... distribute

    (x-4) ^2 = x^2 - 8x + 16
  2. 21 October, 05:42
    0
    (x - 4) ^2 = x^2 - 8*x + 16

    Step-by-step explanation:

    (a - b) ^2 = a^2 - 2*a*b + b^2

    (x - 4) ^2 = x^2 - 2*x*4 + 4^2 = x^2 - 8*x + 16
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