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3 August, 17:18

Elizabeth brought a box of donuts to share. there are two-dozen (24) donuts in the box, all identical in size, shape, and color. threethree are jelly-filled, 44 are lemon-filled, and 1717 are custard-filled. you randomly select one donut, eat it, and select another donut. find the probability of selecting two custardcustard -filled donuts in a row.

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  1. 3 August, 20:41
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    (I'm assuming it's supposed to say 3 jelly-filled, 4 lemon-filled, and 17 custard-filled since there are only 24 donuts)

    this means that 3 out of 24 are jelly (3/24)

    4 out of 24 are lemon (4/24)

    and 17 out of 24 are custard (17/24)

    the probability of eating a custard donut is then 17/24

    now there are 23 donuts left, and 16 are custard. the probability of eating a custard donut is now 16/23. however, the probability of both of these happening is found by multiplying these 2 separate probabilities:

    17/24 * 16/23 = 272/552

    this probability is then simplified:

    (272:8) / (552:8) = 34/69

    so, the answer is 34/69, which is about a 49.3% chance
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