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31 May, 07:25

You have one type of nut that sells for $4.50/lb and another type of nut that sells for $8.80/lb. You would like to have 12.9 lbs of a nut mixture that sells for $8.00/lb. How much of each nut will you need to obtain the desired mixture?

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  1. 31 May, 08:50
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    The quantity of first nut = x = 2.4 lb

    The quantity of second nut = 12.9 - x = 12.9 - 2.4 = 10.5 lb

    Step-by-step explanation:

    Let amount of first type of nut = x

    Amount of second type of nut = 12.9 - x

    Total Cost of first type of nut = 4.5 x

    Total Cost of second type of nut = 8.8 * (12.9 - x)

    Total cost of both type of nut = 8 * 12.9

    Total cost = Cost of first type of nut + Cost of second type of nut

    8 * 12.9 = 4.5 x + 8.8 * (12.9 - x)

    103.2 = 4.5 x + 113.52 - 8.8 x

    8.8 x - 4.5 x = 10.32

    4.3 x = 10.32

    x = 2.4

    Therefore the quantity of first nut = x = 2.4 lb

    The quantity of second nut = 12.9 - x = 12.9 - 2.4 = 10.5 lb
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