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28 March, 13:26

Eight algebra questions (explanations would be appreciated):

Use substitution to solve the following:

1)

y=x²

y=x+2

2)

y=x²+3

y=4x

3)

x²+4y=1

y=x+1

4)

x²-3y=-2

y=4+x

5)

x²-2y=-4

y=6-x

6)

x²+4y=9

y=x-3

7)

x²+5y=16

y+x=2

8)

y=x²-6x

3x-y=-10

+2
Answers (1)
  1. 28 March, 14:22
    0
    Step-by-step explanation:

    1)

    y=x²

    y=x+2

    so: x² = x+2

    x²-x-2 = 0

    (x+1) (x-2) = 0

    x+1=0 or x - 2=0

    x = -1 or x=2

    x = - 1 y = - 1+2 = 1

    x = 2 y=2+2=4

    continu same method
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