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26 July, 08:35

A garage is scheduled to have a temporary gravel floor until the homeowner has a he funds necessary to poor concrete floor. Washed gravel is 105 pounds per cubic foot. F the inside dimension of the garage if the L35' / W. 22' and 18" deep. How much the gravel will be required for the floor. Round the answer to the next whole ton? Ok

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  1. 26 July, 11:06
    0
    842 pounds

    Step-by-step explanation:

    Given in the question,

    dimension of the garage is 35'' by 22'' by 18''

    Total gravel need to be filled

    L x W x H

    35'' x 22'' x 18''

    13860 in³

    1 in³ = 0.000578704 ft³

    13860 in³ = 13860 * 0.000578704 ft³

    = 8.0208 ft³

    Given that gravel is 105 pounds per cubic foot

    so,

    105 x 8.0208

    842.18793

    ≈ 842 pounds
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