The price of a bottle of water at a store decreases from 2.65 to 1.40 round to the nearest tenth of a percent what is the percent decrease in the price of the bottle of water

50% (rounded to the nearest tenth of a percent)

Step-by-step explanation:

In this question, we are asked to find the percentage decrease in the price of the bottle of water.

To do this, what we do is that we subtract the new price from the old price, then we divide the result by the old price and multiply the result by 100.

Mathematically,

Percentage decrease in price = (old price - new price) / old price * 100%

Percentage decrease in price = (2.65-1.4) / 2.65 * 100%

1.25/2.65 * 100% = 47.2%

We were asked to round to the nearest tenth of a percent. This brings our answer to 50%

47.2 %

Step-by-step explanation:

Given:

Initial price, P1 = 2.65

Final price, P2 = 1.40

% price decrease = change in price/initial price * 100

Change in price = P1 - P2

= 2.65 - 1.40

= 1.25

% decrease = 1.25/2.65 * 100

= 47.2 %