A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Of all the vehicles, 10% are black SUVs. What is the probability that an SUV chosen at random is black? Round your answer to the nearest tenth of a percent.

Answer: 0.3

Step-by-step explanation:

From the question,

A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Since 70% are cars, SUV will be (100% - 70%) = 30%. Of all the vehicles, 10% are black SUVs. To calculate the probability than an SUV chosen is black goes thus:

P (A|B) = P (A and B) / P (B)

P (SUV | black) = P (SUV and black) / P (suv)

P (suv | black) = 10% / 30%

P (suv | black) = 0.1/0.3

P (suv | black) = 0.3