Ask Question
13 September, 02:48

Y = 1/3x+3

Y=2x-2

How can I solve of systems of equation substitution.?

+4
Answers (2)
  1. 13 September, 03:00
    0
    x=3

    Step-by-step explanation:

    Since both equations solve for y, set the equations equal to each other:

    1/3x+3 = 2x-2

    Then solve for x:

    1/3x-2x=-2-3

    1/3x-6/3x=-5

    -5/3x=-5

    -5x=-5*3

    -5x=-15

    x=-15/-5

    x=3
  2. 13 September, 04:50
    0
    x=3

    Step-by-step explanation:

    1/3x+3 = 2x-2

    Then solve for x:

    1/3x-2x=-2-3

    1/3x-6/3x=-5

    -5/3x=-5

    -5x=-5*3

    -5x=-15

    x=-15/-5

    x=3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Y = 1/3x+3 Y=2x-2 How can I solve of systems of equation substitution.? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers