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10 January, 20:52

Which function has zeros at x = - 2 and x = 5?

O f (x) = x2 + 2x - 10

o f (x) = x2 - 2x - 10

Of (x) = x2 + 3x - 10

o f (x) = x2 - 3x - 10

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  1. 10 January, 22:53
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    D. Put (x^2 - 3x - 10) into y = on a graphing calculator. If you check the table, both - 2 and 5 have y's of 0.
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