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10 October, 03:47

Write an equation for a rational function with: Vertical asymptotes at x = - 2 and x = - 3 x intercepts at x = - 4 and x = 4 y intercept at 6

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  1. 10 October, 07:27
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    [ - 9 (x^2 - 16) ] / [4 (x^2 + 5x + 6) ] = 0

    Step-by-step explanation:

    Ok this will be a rational function with denominator (x + 2) (x + 3) - to give the vertical asymptotes.

    The numerator will be a (x + 4) (x - 4) to give the x-intercepts. The a is some constant.

    As the y intercept is (0,6) we have:

    6 = a (0-4) (0+4) / (0+2) (0+3)

    6 = - 16a / 6

    -16a = 36

    a = - 36/16 = - 9/4.

    So our equation is - 9 (x^2 - 16) / 4 (x^2 + 5x + 6) = 0.
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