The one to one functions G and H are defined as follow

G={ (-1,1), (3,8), (4,5) (8,-4) }

H (x) = 2x+3

find the following

g^-1 (8) =

h^-1 (x) =

(hoh^-1) (-1) =

Find the solution (s) to x2 - 16x+64 = 0. O A. x = 8 only B. X = 8 and x = - 8 Ο Ο " C. χ = 4 and x = 16 Ο D. X = - 2 and x = 32

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