Simon is doing a card trick using a standard 52-card deck with four suits: hearts, diamonds, spades, and clubs. He shows his friend a card, replaces it, and then shows his friend another card. What is the probability that the first card is not a club and the second card is a diamond?

Question

Mathematics

Keagan Lara

12 January, 04:32

Simon is doing a card trick using a standard 52-card deck with four suits: hearts, diamonds, spades, and clubs. He shows his friend a card, replaces it, and then shows his friend another card. What is the probability that the first card is not a club and the second card is a diamond?

+3

Answers (1)

Know the Answer?

Luis Bradley · Answer 1

52 cards in 4 suits = 1/4 of 52 per suit.

52 divided by 4 = 13

therefore each suit has 13 cards.

therefore 1st card not being a club = a 39/52 chance because 52-13 (clubs) = 39

2nd card = 13/52 chance because there are 13 diamonds in the pack.