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8 March, 00:50

What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y - 1?

P = 2x + 2y + 18

P = 2x + 2y + 14

P = x + y-9

P = x + y + 7

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  1. 8 March, 02:27
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    P=2x+2y+14

    Step-by-step explanation:

    Perimeter (P) of a rectangle = 2 (l+b)

    where l is the length and b is the width of the rectangle.

    Here, l = x+8

    and, b = y-1

    so, P = 2{ (x+8) + (y-1) }

    = 2 (x+8+y-1)

    = 2 (x+y+7)

    =2x+2y+14
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