Ask Question
2 December, 23:07

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

+3
Answers (1)
  1. 2 December, 23:22
    0
    55

    Step-by-step explanation:

    The five smallest prime numbers are 2, 3, 5, 7 and 11.

    2 * 3 * 5 * 7 * 11

    = 2310

    Divide by 42.

    2310/42

    = 55
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the remainder when the product of the 5 smallest prime numbers is divided by 42? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers