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13 April, 22:28

The sum of the measures of the angles of a parallelogram is 360°. In the parallelogram on the right, angles A and D have the same measure as well as angles C and B. If the measure of angle C is eight timeseight times the measure of angle A, find the measure of each angle.

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  1. 14 April, 00:00
    0
    A = 20 degree

    B = 160 degree

    C = 160 degree

    D = 20 degree

    Step-by-step explanation:

    If the measure of angle C is eight timeseight times the measure of angle A

    That means C = 8A

    But According to the question, angles A and D have the same measure as well as angles C and B.

    That is, B = 8A and D = A

    If A + B + C + D = 360

    Let us substitute for B, C and D

    A + 8A + 8A + A = 360

    18A = 360

    A = 360/18 = 20

    Therefore

    A = 20 degree

    B = 8 * 20 = 160 degree

    C = 8 * 20 = 160 degree

    D = 20 degree
  2. 14 April, 00:11
    0
    Answer: The angles measure A = 20 degrees, B = 160 degrees, C = 160 degrees and D = 20 degrees.

    Step-by-step explanation: One of the properties of a parallelogram is that opposite angles are equal. Hence we are given that angles A and D have the same measurement. Angles C and B also have the same measurement since they are also opposite each other. If angle C is eight times angle A, then angle C can be expressed as 8A, and the same applies to angle B. So, the four angles can be expressed as;

    A + A + 8A + 8A = 360

    (The sum of the four angles in a parallelogram equals 360 degrees)

    2A + 16A = 360

    18A = 360

    Divide both sides of the equation by 18

    A = 20

    Therefore angle A = 20 and angle D = 20

    Angle B = 160 and angle C = 160
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