X2 + y2 + 6x - 2y+3 = 0?

What is the radius of a circle with the equation

Step-by-step explanation:

hello : write this expression

X² + y² + 6x - 2y+3 = 0 in the standard form

(x²+6x) + (y²-2y) + 3 = 0

(x²+6x+9 - 9) + (y²-2y+1 - 1) + 3 = 0

(x²+6x+9) - 9 + (y²-2y+1) - 1 + 3 = 0

(x+3) ² + (y-1) ² = 7 (the standard form)

but : 7 = (√7) ²

the radius is : √7