Is the function even, odd or neither?

f (x) = |x| + 1

Your answer:

Even

Odd

Neither

Answer: Even

Step-by-step explanation:

This graph has been translated up by one unit but is still symmetrical about the y axis.

A simple proof would be to check if f (x) = f (-x). If it does, then it is even.

To check for an odd function, check if f (-x) = - f (x). If it does, then it is even.

To check for neither, f (-x) will not equal - f (x)

Answer: Even

Explanation