According to a survey of 100 people regarding their movie attendance in the last year, 40 had seen a science fiction movie, 55 had seen an adventure movie, and 20 had seen a horror movie. Moreover, 25 had seen a science fiction movie and an adventure movie, 5 had seen an adventure movie and a horror movie, and 15 had seen a science fiction movie and a horror movie. Only 5 people had seen a movie from all three categories.

The probability that at least one movie had seen P (S∪ (AD) ∪H) = 0.75

Step-by-step explanation:

The total number of movie attendance in the last year n = 100

Let 'S' be the event had seen science fiction movie

The probability of that the event had seen science fiction movie

P (S) = 40/100 = 0.4

Let 'AD' be the event had seen adventure movie

the probability of that the event had seen adventure movie

P (AD) = 55/100 = 0.55

Let 'H' be the event had seen Horror movie

The probability of that the event had seen Horror movie

P (H) = 20/100 = 0.2

given data 25 had seen a science fiction movie and an adventure movie

The probability of that the seen a science fiction movie and an adventure movie

that is P (S∩ (AD)) = 25/100=0.25

Given 5 had seen an adventure movie and a horror movie

The probability of that the seen adventure movie and a horror movie

That is P ((AD) ∩ H) = 5/100=0.05

Given 5 had seen an science movie and a horror movie

The probability of that the seen science movie and a horror movie

That is P ((S∩ H) = 15/100=0.15

Given only 5 people had seen a movie from all three categories.

The probability of that the seen a movie from all three categories.

That is P (S∩ (AD) ∩H) = 5/100=0.05

The probability that at least one movie had seen P (S∪ (AD) ∪H) =

= P (S) + P (AD) + P (H) - P (S∩ (AD) - P ((AD) ∩ H) - P ((S∩ H) + P (S∩ (AD) ∩H)

= 0.4+0.55+0.2-0.25-0.05-0.15+0.05

= 0.75