If c (x) = 4x - 2 and d (x) = x2 + 5x, what is (c0d) (x)

The answer is (cod) (x) = 4x^2 + 20x - 2

Step-by-step explanation:

In order to find (cod) (x), we need to start with the c (x) equation and then input the d (x) equation for every x in the c (x) equation.

c (x) = 4x - 2

(cod) (x) = 4 (x^2 + 5x) - 2

(cod) (x) = 4x^2 + 20x - 2