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27 July, 18:35

If c (x) = 4x - 2 and d (x) = x2 + 5x, what is (c0d) (x)

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  1. 27 July, 19:30
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    The answer is (cod) (x) = 4x^2 + 20x - 2

    Step-by-step explanation:

    In order to find (cod) (x), we need to start with the c (x) equation and then input the d (x) equation for every x in the c (x) equation.

    c (x) = 4x - 2

    (cod) (x) = 4 (x^2 + 5x) - 2

    (cod) (x) = 4x^2 + 20x - 2
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